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114315013301 is a prime number
BaseRepresentation
bin110101001110110110…
…1001010110010110101
3101221001210212100211112
41222131231022302311
53333104120411201
6124303211244405
711154555403106
oct1523555126265
9357053770745
10114315013301
1144531932505
121a1a3a49705
13aa1a474b08
1457662d83ad
152e90d450bb
hex1a9db4acb5

114315013301 has 2 divisors, whose sum is σ = 114315013302. Its totient is φ = 114315013300.

The previous prime is 114315013273. The next prime is 114315013313. The reversal of 114315013301 is 103310513411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107158022500 + 7156990801 = 327350^2 + 84599^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114315013301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114315013321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57157506650 + 57157506651.

It is an arithmetic number, because the mean of its divisors is an integer number (57157506651).

Almost surely, 2114315013301 is an apocalyptic number.

It is an amenable number.

114315013301 is a deficient number, since it is larger than the sum of its proper divisors (1).

114315013301 is an equidigital number, since it uses as much as digits as its factorization.

114315013301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 23.

Adding to 114315013301 its reverse (103310513411), we get a palindrome (217625526712).

The spelling of 114315013301 in words is "one hundred fourteen billion, three hundred fifteen million, thirteen thousand, three hundred one".