Base | Representation |
---|---|
bin | 1010011001011010010110… |
… | …0011010001000101011111 |
3 | 1111110212011211000012120121 |
4 | 2212112211203101011133 |
5 | 2444244042434212234 |
6 | 40151351021055411 |
7 | 2256624552100555 |
oct | 246264543210537 |
9 | 44425154005517 |
10 | 11431685460319 |
11 | 3708172467653 |
12 | 13476543b7567 |
13 | 64c007382a87 |
14 | 2b7421961bd5 |
15 | 14c56eb5c4b4 |
hex | a65a58d115f |
11431685460319 has 2 divisors, whose sum is σ = 11431685460320. Its totient is φ = 11431685460318.
The previous prime is 11431685460301. The next prime is 11431685460407. The reversal of 11431685460319 is 91306458613411.
11431685460319 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11431685460319 - 237 = 11294246506847 is a prime.
It is a super-4 number, since 4×114316854603194 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11431685466319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5715842730159 + 5715842730160.
It is an arithmetic number, because the mean of its divisors is an integer number (5715842730160).
Almost surely, 211431685460319 is an apocalyptic number.
11431685460319 is a deficient number, since it is larger than the sum of its proper divisors (1).
11431685460319 is an equidigital number, since it uses as much as digits as its factorization.
11431685460319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 52.
The spelling of 11431685460319 in words is "eleven trillion, four hundred thirty-one billion, six hundred eighty-five million, four hundred sixty thousand, three hundred nineteen".
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