Base | Representation |
---|---|
bin | 10000101000101110011… |
… | …111111011110010101111 |
3 | 11001021220110102201002201 |
4 | 100220232133323302233 |
5 | 122212324301032142 |
6 | 2233110423202331 |
7 | 145411405524142 |
oct | 20505637736257 |
9 | 4037813381081 |
10 | 1143241424047 |
11 | 400933a85988 |
12 | 1656992a63a7 |
13 | 83a65571118 |
14 | 3d494364059 |
15 | 1eb11d19ab7 |
hex | 10a2e7fbcaf |
1143241424047 has 2 divisors, whose sum is σ = 1143241424048. Its totient is φ = 1143241424046.
The previous prime is 1143241423967. The next prime is 1143241424057. The reversal of 1143241424047 is 7404241423411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1143241424047 - 211 = 1143241421999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1143241423997 and 1143241424015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1143241424057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571620712023 + 571620712024.
It is an arithmetic number, because the mean of its divisors is an integer number (571620712024).
Almost surely, 21143241424047 is an apocalyptic number.
1143241424047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1143241424047 is an equidigital number, since it uses as much as digits as its factorization.
1143241424047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86016, while the sum is 37.
Adding to 1143241424047 its reverse (7404241423411), we get a palindrome (8547482847458).
The spelling of 1143241424047 in words is "one trillion, one hundred forty-three billion, two hundred forty-one million, four hundred twenty-four thousand, forty-seven".
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