Base | Representation |
---|---|
bin | 10000101000110010001… |
… | …011010000110110110111 |
3 | 11001022001202111220000222 |
4 | 100220302023100312313 |
5 | 122212441044123132 |
6 | 2233120505324555 |
7 | 145413055060544 |
oct | 20506213206667 |
9 | 4038052456028 |
10 | 1143303114167 |
11 | 400965890655 |
12 | 1656b5a9675b |
13 | 83a75290456 |
14 | 3d49c621bcb |
15 | 1eb17453412 |
hex | 10a322d0db7 |
1143303114167 has 2 divisors, whose sum is σ = 1143303114168. Its totient is φ = 1143303114166.
The previous prime is 1143303114157. The next prime is 1143303114221. The reversal of 1143303114167 is 7614113033411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1143303114167 - 228 = 1143034678711 is a prime.
It is a super-2 number, since 2×11433031141672 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1143303114157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571651557083 + 571651557084.
It is an arithmetic number, because the mean of its divisors is an integer number (571651557084).
Almost surely, 21143303114167 is an apocalyptic number.
1143303114167 is a deficient number, since it is larger than the sum of its proper divisors (1).
1143303114167 is an equidigital number, since it uses as much as digits as its factorization.
1143303114167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 35.
Adding to 1143303114167 its reverse (7614113033411), we get a palindrome (8757416147578).
The spelling of 1143303114167 in words is "one trillion, one hundred forty-three billion, three hundred three million, one hundred fourteen thousand, one hundred sixty-seven".
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