Base | Representation |
---|---|
bin | 11001111111101110100101… |
… | …100011101100100101000111 |
3 | 112222210220000221222021101220 |
4 | 121333232211203230211013 |
5 | 104441142342041104003 |
6 | 1043054413454051423 |
7 | 33040051445560650 |
oct | 3177564543544507 |
9 | 488726027867356 |
10 | 114330512050503 |
11 | 3347a33050a221 |
12 | 109a60291a9b73 |
13 | 4ba44233a4938 |
14 | 20338aa83c527 |
15 | d33eeb8ee353 |
hex | 67fba58ec947 |
114330512050503 has 32 divisors (see below), whose sum is σ = 177642763545600. Its totient is φ = 64049318651136.
The previous prime is 114330512050487. The next prime is 114330512050543. The reversal of 114330512050503 is 305050215033411.
It is not a de Polignac number, because 114330512050503 - 24 = 114330512050487 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114330512050543) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 38411283 + ... + 41280596.
It is an arithmetic number, because the mean of its divisors is an integer number (5551336360800).
Almost surely, 2114330512050503 is an apocalyptic number.
114330512050503 is a deficient number, since it is larger than the sum of its proper divisors (63312251495097).
114330512050503 is a wasteful number, since it uses less digits than its factorization.
114330512050503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79693231.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 114330512050503 its reverse (305050215033411), we get a palindrome (419380727083914).
The spelling of 114330512050503 in words is "one hundred fourteen trillion, three hundred thirty billion, five hundred twelve million, fifty thousand, five hundred three".
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