11433131131200 has 168 divisors, whose sum is σ = 38125119970080. Its totient is φ = 2998853990400.

The previous prime is 11433131131141. The next prime is 11433131131223. The reversal of 11433131131200 is 213113133411.

It is a super-2 number, since 2×11433131131200² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19230990 + ... + 19816589.

Almost surely, 2^{11433131131200} is an apocalyptic number.

11433131131200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11433131131200 is an abundant number, since it is smaller than the sum of its proper divisors (26691988838880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11433131131200 is a wasteful number, since it uses less digits than its factorization.

11433131131200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39047665 (or 39047650 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 11433131131200 its reverse (213113133411), we get a palindrome (11646244264611).

The spelling of 11433131131200 in words is "eleven trillion, four hundred thirty-three billion, one hundred thirty-one million, one hundred thirty-one thousand, two hundred".