Search a number
-
+
114331326539 is a prime number
BaseRepresentation
bin110101001111010101…
…1011001100001001011
3101221002221120011101112
41222132223121201023
53333122304422124
6124304553040535
711155144145423
oct1523653314113
9357087504345
10114331326539
1144540064921
121a1a93b614b
13aa20967111
145768543483
152e924b890e
hex1a9ead984b

114331326539 has 2 divisors, whose sum is σ = 114331326540. Its totient is φ = 114331326538.

The previous prime is 114331326491. The next prime is 114331326569. The reversal of 114331326539 is 935623133411.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114331326539 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114331326496 and 114331326505.

It is not a weakly prime, because it can be changed into another prime (114331326569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57165663269 + 57165663270.

It is an arithmetic number, because the mean of its divisors is an integer number (57165663270).

Almost surely, 2114331326539 is an apocalyptic number.

114331326539 is a deficient number, since it is larger than the sum of its proper divisors (1).

114331326539 is an equidigital number, since it uses as much as digits as its factorization.

114331326539 is an evil number, because the sum of its binary digits is even.

The product of its digits is 174960, while the sum is 41.

The spelling of 114331326539 in words is "one hundred fourteen billion, three hundred thirty-one million, three hundred twenty-six thousand, five hundred thirty-nine".