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114331326569 is a prime number
BaseRepresentation
bin110101001111010101…
…1011001100001101001
3101221002221120011102122
41222132223121201221
53333122304422234
6124304553041025
711155144145465
oct1523653314151
9357087504378
10114331326569
1144540064949
121a1a93b6175
13aa20967135
1457685434a5
152e924b892e
hex1a9ead9869

114331326569 has 2 divisors, whose sum is σ = 114331326570. Its totient is φ = 114331326568.

The previous prime is 114331326539. The next prime is 114331326649. The reversal of 114331326569 is 965623133411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113374970944 + 956355625 = 336712^2 + 30925^2 .

It is an emirp because it is prime and its reverse (965623133411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114331326569 is a prime.

It is a super-2 number, since 2×1143313265692 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114331326539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57165663284 + 57165663285.

It is an arithmetic number, because the mean of its divisors is an integer number (57165663285).

Almost surely, 2114331326569 is an apocalyptic number.

It is an amenable number.

114331326569 is a deficient number, since it is larger than the sum of its proper divisors (1).

114331326569 is an equidigital number, since it uses as much as digits as its factorization.

114331326569 is an evil number, because the sum of its binary digits is even.

The product of its digits is 349920, while the sum is 44.

The spelling of 114331326569 in words is "one hundred fourteen billion, three hundred thirty-one million, three hundred twenty-six thousand, five hundred sixty-nine".