11433203231 has 2 divisors, whose sum is σ = 11433203232. Its totient is φ = 11433203230.

The previous prime is 11433203123. The next prime is 11433203237. The reversal of 11433203231 is 13230233411.

Together with previous prime (11433203123) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11433203231 is a prime.

It is a super-4 number, since 4×11433203231⁴ (a number of 41 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 11433203197 and 11433203206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11433203237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716601615 + 5716601616.

It is an arithmetic number, because the mean of its divisors is an integer number (5716601616).

Almost surely, 2^11433203231 is an apocalyptic number.

11433203231 is a deficient number, since it is larger than the sum of its proper divisors (1).

11433203231 is an equidigital number, since it uses as much as digits as its factorization.

11433203231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11433203231 its reverse (13230233411), we get a palindrome (24663436642).

The spelling of 11433203231 in words is "eleven billion, four hundred thirty-three million, two hundred three thousand, two hundred thirty-one".