11433391213 has 2 divisors, whose sum is σ = 11433391214. Its totient is φ = 11433391212.

The previous prime is 11433391199. The next prime is 11433391219. The reversal of 11433391213 is 31219333411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5886418729 + 5546972484 = 76723^2 + 74478^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11433391213 is a prime.

It is a super-2 number, since 2×11433391213² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11433391219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5716695606 + 5716695607.

It is an arithmetic number, because the mean of its divisors is an integer number (5716695607).

Almost surely, 2^11433391213 is an apocalyptic number.

It is an amenable number.

11433391213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11433391213 is an equidigital number, since it uses as much as digits as its factorization.

11433391213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5832, while the sum is 31.

The spelling of 11433391213 in words is "eleven billion, four hundred thirty-three million, three hundred ninety-one thousand, two hundred thirteen".