1143340111 has 2 divisors, whose sum is σ = 1143340112. Its totient is φ = 1143340110.

The previous prime is 1143340103. The next prime is 1143340123. The reversal of 1143340111 is 1110433411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1143340111 - 2³ = 1143340103 is a prime.

It is a super-3 number, since 3×1143340111³ (a number of 28 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1143320111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571670055 + 571670056.

It is an arithmetic number, because the mean of its divisors is an integer number (571670056).

Almost surely, 2^1143340111 is an apocalyptic number.

1143340111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1143340111 is an equidigital number, since it uses as much as digits as its factorization.

1143340111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1143340111 is about 33813.3126297912. The cubic root of 1143340111 is about 1045.6631737482.

Adding to 1143340111 its reverse (1110433411), we get a palindrome (2253773522).

The spelling of 1143340111 in words is "one billion, one hundred forty-three million, three hundred forty thousand, one hundred eleven".