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114340024103161 is a prime number
BaseRepresentation
bin11001111111110111011100…
…100001010011000011111001
3112222211210120212120121121111
4121333313130201103003321
5104441321332132300121
61043103025410240321
733040536246644623
oct3177673441230371
9488753525517544
10114340024103161
113348337184a16a
12109a7a428860a1
134ba52aac69c6c
14203412dc65c13
15d343a6a252e1
hex67fddc8530f9

114340024103161 has 2 divisors, whose sum is σ = 114340024103162. Its totient is φ = 114340024103160.

The previous prime is 114340024103143. The next prime is 114340024103237. The reversal of 114340024103161 is 161301420043411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106449155456400 + 7890868646761 = 10317420^2 + 2809069^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114340024103161 is a prime.

It is a super-2 number, since 2×1143400241031612 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114340024103111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57170012051580 + 57170012051581.

It is an arithmetic number, because the mean of its divisors is an integer number (57170012051581).

Almost surely, 2114340024103161 is an apocalyptic number.

It is an amenable number.

114340024103161 is a deficient number, since it is larger than the sum of its proper divisors (1).

114340024103161 is an equidigital number, since it uses as much as digits as its factorization.

114340024103161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 114340024103161 its reverse (161301420043411), we get a palindrome (275641444146572).

The spelling of 114340024103161 in words is "one hundred fourteen trillion, three hundred forty billion, twenty-four million, one hundred three thousand, one hundred sixty-one".