Base | Representation |
---|---|
bin | 11001111111110111011100… |
… | …100001010011000011100111 |
3 | 112222211210120212120121120211 |
4 | 121333313130201103003213 |
5 | 104441321332132300033 |
6 | 1043103025410240251 |
7 | 33040536246644566 |
oct | 3177673441230347 |
9 | 488753525517524 |
10 | 114340024103143 |
11 | 3348337184a153 |
12 | 109a7a42886087 |
13 | 4ba52aac69c57 |
14 | 203412dc65bdd |
15 | d343a6a252cd |
hex | 67fddc8530e7 |
114340024103143 has 2 divisors, whose sum is σ = 114340024103144. Its totient is φ = 114340024103142.
The previous prime is 114340024103111. The next prime is 114340024103161. The reversal of 114340024103143 is 341301420043411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114340024103143 - 25 = 114340024103111 is a prime.
It is a super-2 number, since 2×1143400241031432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114340024107143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57170012051571 + 57170012051572.
It is an arithmetic number, because the mean of its divisors is an integer number (57170012051572).
Almost surely, 2114340024103143 is an apocalyptic number.
114340024103143 is a deficient number, since it is larger than the sum of its proper divisors (1).
114340024103143 is an equidigital number, since it uses as much as digits as its factorization.
114340024103143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 114340024103143 its reverse (341301420043411), we get a palindrome (455641444146554).
The spelling of 114340024103143 in words is "one hundred fourteen trillion, three hundred forty billion, twenty-four million, one hundred three thousand, one hundred forty-three".
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