Base | Representation |
---|---|
bin | 110101001111100111… |
… | …0001001000110011011 |
3 | 101221010120200212221011 |
4 | 1222133032021012123 |
5 | 3333132122344311 |
6 | 124305520154351 |
7 | 11155314440644 |
oct | 1523716110633 |
9 | 357116625834 |
10 | 114340434331 |
11 | 44545215722 |
12 | 1a1b04689b7 |
13 | aa22805846 |
14 | 57698346cb |
15 | 2e931b7321 |
hex | 1a9f38919b |
114340434331 has 2 divisors, whose sum is σ = 114340434332. Its totient is φ = 114340434330.
The previous prime is 114340434293. The next prime is 114340434337. The reversal of 114340434331 is 133434043411.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114340434331 - 29 = 114340433819 is a prime.
It is a super-2 number, since 2×1143404343312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114340434293 and 114340434302.
It is not a weakly prime, because it can be changed into another prime (114340434337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57170217165 + 57170217166.
It is an arithmetic number, because the mean of its divisors is an integer number (57170217166).
Almost surely, 2114340434331 is an apocalyptic number.
114340434331 is a deficient number, since it is larger than the sum of its proper divisors (1).
114340434331 is an equidigital number, since it uses as much as digits as its factorization.
114340434331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 114340434331 its reverse (133434043411), we get a palindrome (247774477742).
The spelling of 114340434331 in words is "one hundred fourteen billion, three hundred forty million, four hundred thirty-four thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.060 sec. • engine limits •