1143440041 has 2 divisors, whose sum is σ = 1143440042. Its totient is φ = 1143440040.

The previous prime is 1143440003. The next prime is 1143440063. The reversal of 1143440041 is 1400443411.

It is an a-pointer prime, because the next prime (1143440063) can be obtained adding 1143440041 to its sum of digits (22).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 576000000 + 567440041 = 24000^2 + 23821^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1143440041 is a prime.

It is a super-3 number, since 3×1143440041³ (a number of 28 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1143439994 and 1143440021.

It is not a weakly prime, because it can be changed into another prime (1143440741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571720020 + 571720021.

It is an arithmetic number, because the mean of its divisors is an integer number (571720021).

Almost surely, 2^1143440041 is an apocalyptic number.

It is an amenable number.

1143440041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1143440041 is an equidigital number, since it uses as much as digits as its factorization.

1143440041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 22.

The square root of 1143440041 is about 33814.7902699396. The cubic root of 1143440041 is about 1045.6936371469.

Adding to 1143440041 its reverse (1400443411), we get a palindrome (2543883452).

The spelling of 1143440041 in words is "one billion, one hundred forty-three million, four hundred forty thousand, forty-one".