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11434401133 = 25146797549
BaseRepresentation
bin10101010011000101…
…10001110101101101
31002111212211202120021
422221202301311231
5141404201314013
65130342522141
7553232543311
oct125142616555
932455752507
1011434401133
11493846a8a1
122271436351
131102c2223c
147a686bb41
1546dc9aa8d
hex2a98b1d6d

11434401133 has 8 divisors (see below), whose sum is σ = 11504656800. Its totient is φ = 11364342000.

The previous prime is 11434401089. The next prime is 11434401221. The reversal of 11434401133 is 33110443411.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11434401133 - 213 = 11434392941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11434401098 and 11434401107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11434401233) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 68443 + ... + 165991.

It is an arithmetic number, because the mean of its divisors is an integer number (1438082100).

Almost surely, 211434401133 is an apocalyptic number.

It is an amenable number.

11434401133 is a deficient number, since it is larger than the sum of its proper divisors (70255667).

11434401133 is an equidigital number, since it uses as much as digits as its factorization.

11434401133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98267.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11434401133 its reverse (33110443411), we get a palindrome (44544844544).

The spelling of 11434401133 in words is "eleven billion, four hundred thirty-four million, four hundred one thousand, one hundred thirty-three".

Divisors: 1 251 467 97549 117217 24484799 45555383 11434401133