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11434421263 is a prime number
BaseRepresentation
bin10101010011000101…
…10110110000001111
31002111212212210011211
422221202312300033
5141404202440023
65130343155251
7553232656066
oct125142666017
932455783154
1011434421263
114938483a31
122271445b27
131102c2b455
147a68751dd
1546dca1a0d
hex2a98b6c0f

11434421263 has 2 divisors, whose sum is σ = 11434421264. Its totient is φ = 11434421262.

The previous prime is 11434421209. The next prime is 11434421267. The reversal of 11434421263 is 36212443411.

11434421263 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (36212443411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11434421263 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11434421267) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5717210631 + 5717210632.

It is an arithmetic number, because the mean of its divisors is an integer number (5717210632).

Almost surely, 211434421263 is an apocalyptic number.

11434421263 is a deficient number, since it is larger than the sum of its proper divisors (1).

11434421263 is an equidigital number, since it uses as much as digits as its factorization.

11434421263 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824, while the sum is 31.

Adding to 11434421263 its reverse (36212443411), we get a palindrome (47646864674).

The spelling of 11434421263 in words is "eleven billion, four hundred thirty-four million, four hundred twenty-one thousand, two hundred sixty-three".