Base | Representation |
---|---|
bin | 11010000000000101111000… |
… | …111011011110001110100111 |
3 | 112222220021121201111220110211 |
4 | 122000011320323132032213 |
5 | 104442100112434042411 |
6 | 1043114112350200251 |
7 | 33041625500232535 |
oct | 3200057073361647 |
9 | 488807551456424 |
10 | 114355533112231 |
11 | 33489a00221234 |
12 | 109aaa507b3087 |
13 | 4ba68b00a38c8 |
14 | 2034ba1909155 |
15 | d349b3382221 |
hex | 680178ede3a7 |
114355533112231 has 2 divisors, whose sum is σ = 114355533112232. Its totient is φ = 114355533112230.
The previous prime is 114355533112153. The next prime is 114355533112253. The reversal of 114355533112231 is 132211335553411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114355533112231 - 27 = 114355533112103 is a prime.
It is a super-2 number, since 2×1143555331122312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114355533112031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57177766556115 + 57177766556116.
It is an arithmetic number, because the mean of its divisors is an integer number (57177766556116).
Almost surely, 2114355533112231 is an apocalyptic number.
114355533112231 is a deficient number, since it is larger than the sum of its proper divisors (1).
114355533112231 is an equidigital number, since it uses as much as digits as its factorization.
114355533112231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 162000, while the sum is 40.
Adding to 114355533112231 its reverse (132211335553411), we get a palindrome (246566868665642).
The spelling of 114355533112231 in words is "one hundred fourteen trillion, three hundred fifty-five billion, five hundred thirty-three million, one hundred twelve thousand, two hundred thirty-one".
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