Base | Representation |
---|---|
bin | 10000101001011010001… |
… | …111000010111111101011 |
3 | 11001100210121011010001222 |
4 | 100221122033002333223 |
5 | 122220330122211403 |
6 | 2233311314332255 |
7 | 145435525466663 |
oct | 20513217027753 |
9 | 4040717133058 |
10 | 1143975194603 |
11 | 4011801a062a |
12 | 165862b8a08b |
13 | 83b515a5797 |
14 | 3d5239ad1a3 |
15 | 1eb5645d338 |
hex | 10a5a3c2feb |
1143975194603 has 2 divisors, whose sum is σ = 1143975194604. Its totient is φ = 1143975194602.
The previous prime is 1143975194477. The next prime is 1143975194651. The reversal of 1143975194603 is 3064915793411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1143975194603 - 218 = 1143974932459 is a prime.
It is not a weakly prime, because it can be changed into another prime (1143975194903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 571987597301 + 571987597302.
It is an arithmetic number, because the mean of its divisors is an integer number (571987597302).
Almost surely, 21143975194603 is an apocalyptic number.
1143975194603 is a deficient number, since it is larger than the sum of its proper divisors (1).
1143975194603 is an equidigital number, since it uses as much as digits as its factorization.
1143975194603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 53.
The spelling of 1143975194603 in words is "one trillion, one hundred forty-three billion, nine hundred seventy-five million, one hundred ninety-four thousand, six hundred three".
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