Base | Representation |
---|---|
bin | 10000101001011011110… |
… | …010000010000001100111 |
3 | 11001100212101222102102112 |
4 | 100221123302002001213 |
5 | 122220403243033022 |
6 | 2233314042431235 |
7 | 145436262161651 |
oct | 20513362020147 |
9 | 4040771872375 |
10 | 1144001142887 |
11 | 401193903999 |
12 | 16586b80251b |
13 | 83b56a8c4b5 |
14 | 3d5272056d1 |
15 | 1eb588868e2 |
hex | 10a5bc82067 |
1144001142887 has 2 divisors, whose sum is σ = 1144001142888. Its totient is φ = 1144001142886.
The previous prime is 1144001142871. The next prime is 1144001142901. The reversal of 1144001142887 is 7882411004411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1144001142887 - 24 = 1144001142871 is a prime.
It is a super-2 number, since 2×11440011428872 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1144001142827) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572000571443 + 572000571444.
It is an arithmetic number, because the mean of its divisors is an integer number (572000571444).
Almost surely, 21144001142887 is an apocalyptic number.
1144001142887 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144001142887 is an equidigital number, since it uses as much as digits as its factorization.
1144001142887 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57344, while the sum is 41.
The spelling of 1144001142887 in words is "one trillion, one hundred forty-four billion, one million, one hundred forty-two thousand, eight hundred eighty-seven".
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