Base | Representation |
---|---|
bin | 110101010001011001… |
… | …0100011001100000111 |
3 | 101221021202100212221101 |
4 | 1222202302203030013 |
5 | 3333242434410043 |
6 | 124315455400531 |
7 | 11156642406436 |
oct | 1524262431407 |
9 | 357252325841 |
10 | 114400310023 |
11 | 44575aa116a |
12 | 1a208523147 |
13 | aa3203b04c |
14 | 577377d11d |
15 | 2e9859324d |
hex | 1aa2ca3307 |
114400310023 has 2 divisors, whose sum is σ = 114400310024. Its totient is φ = 114400310022.
The previous prime is 114400309981. The next prime is 114400310053. The reversal of 114400310023 is 320013004411.
It is a strong prime.
It is an emirp because it is prime and its reverse (320013004411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114400310023 - 213 = 114400301831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114400310053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57200155011 + 57200155012.
It is an arithmetic number, because the mean of its divisors is an integer number (57200155012).
Almost surely, 2114400310023 is an apocalyptic number.
114400310023 is a deficient number, since it is larger than the sum of its proper divisors (1).
114400310023 is an equidigital number, since it uses as much as digits as its factorization.
114400310023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 114400310023 its reverse (320013004411), we get a palindrome (434413314434).
The spelling of 114400310023 in words is "one hundred fourteen billion, four hundred million, three hundred ten thousand, twenty-three".
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