Base | Representation |
---|---|
bin | 1010011001111001110001… |
… | …0010101011111001100111 |
3 | 1111111122221122011221001010 |
4 | 2212132130102223321213 |
5 | 2444413331213201401 |
6 | 40155304003433303 |
7 | 2260343561001033 |
oct | 246363422537147 |
9 | 44448848157033 |
10 | 11440120053351 |
11 | 37108005881a0 |
12 | 1349209085833 |
13 | 64ca4c959c22 |
14 | 2b79c1c371c3 |
15 | 14c8b53a0ed6 |
hex | a679c4abe67 |
11440120053351 has 16 divisors (see below), whose sum is σ = 16644321383040. Its totient is φ = 6931678276320.
The previous prime is 11440120053347. The next prime is 11440120053353. The reversal of 11440120053351 is 15335002104411.
It is not a de Polignac number, because 11440120053351 - 22 = 11440120053347 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11440120053353) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43060981 + ... + 43325838.
It is an arithmetic number, because the mean of its divisors is an integer number (1040270086440).
Almost surely, 211440120053351 is an apocalyptic number.
11440120053351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11440120053351 is a deficient number, since it is larger than the sum of its proper divisors (5204201329689).
11440120053351 is a wasteful number, since it uses less digits than its factorization.
11440120053351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86390846.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 11440120053351 its reverse (15335002104411), we get a palindrome (26775122157762).
The spelling of 11440120053351 in words is "eleven trillion, four hundred forty billion, one hundred twenty million, fifty-three thousand, three hundred fifty-one".
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