Base | Representation |
---|---|
bin | 10000101001011100011… |
… | …100110010101010001101 |
3 | 11001100220012001220122002 |
4 | 100221130130302222031 |
5 | 122220414130232031 |
6 | 2233315123002045 |
7 | 145436456356001 |
oct | 20513434625215 |
9 | 4040805056562 |
10 | 1144012352141 |
11 | 40119a16a63a |
12 | 165873509325 |
13 | 83b591b55a9 |
14 | 3d5288c2701 |
15 | 1eb5984cccb |
hex | 10a5c732a8d |
1144012352141 has 2 divisors, whose sum is σ = 1144012352142. Its totient is φ = 1144012352140.
The previous prime is 1144012352137. The next prime is 1144012352167. The reversal of 1144012352141 is 1412532104411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1073407890916 + 70604461225 = 1036054^2 + 265715^2 .
It is a cyclic number.
It is not a de Polignac number, because 1144012352141 - 22 = 1144012352137 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1144012352111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572006176070 + 572006176071.
It is an arithmetic number, because the mean of its divisors is an integer number (572006176071).
Almost surely, 21144012352141 is an apocalyptic number.
It is an amenable number.
1144012352141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144012352141 is an equidigital number, since it uses as much as digits as its factorization.
1144012352141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 29.
Adding to 1144012352141 its reverse (1412532104411), we get a palindrome (2556544456552).
The spelling of 1144012352141 in words is "one trillion, one hundred forty-four billion, twelve million, three hundred fifty-two thousand, one hundred forty-one".
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