Base | Representation |
---|---|
bin | 1010011001111010001100… |
… | …1011001010000100111001 |
3 | 1111111200020200110020221021 |
4 | 2212132203023022010321 |
5 | 2444414100243122223 |
6 | 40155323250342441 |
7 | 2260346462312305 |
oct | 246364313120471 |
9 | 44450220406837 |
10 | 11440235520313 |
11 | 371085a783236 |
12 | 134923b88aa21 |
13 | 64ca6a857782 |
14 | 2b79d32d2d05 |
15 | 14c8c05ad65d |
hex | a67a32ca139 |
11440235520313 has 2 divisors, whose sum is σ = 11440235520314. Its totient is φ = 11440235520312.
The previous prime is 11440235520269. The next prime is 11440235520323. The reversal of 11440235520313 is 31302553204411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11365710888249 + 74524632064 = 3371307^2 + 272992^2 .
It is a cyclic number.
It is not a de Polignac number, because 11440235520313 - 233 = 11431645585721 is a prime.
It is not a weakly prime, because it can be changed into another prime (11440235520323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5720117760156 + 5720117760157.
It is an arithmetic number, because the mean of its divisors is an integer number (5720117760157).
Almost surely, 211440235520313 is an apocalyptic number.
It is an amenable number.
11440235520313 is a deficient number, since it is larger than the sum of its proper divisors (1).
11440235520313 is an equidigital number, since it uses as much as digits as its factorization.
11440235520313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 11440235520313 its reverse (31302553204411), we get a palindrome (42742788724724).
The spelling of 11440235520313 in words is "eleven trillion, four hundred forty billion, two hundred thirty-five million, five hundred twenty thousand, three hundred thirteen".
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