Base | Representation |
---|---|
bin | 110101010001011110… |
… | …1111101011111011101 |
3 | 101221021221222212020221 |
4 | 1222202331331133131 |
5 | 3333244221120331 |
6 | 124320043441341 |
7 | 11160010005460 |
oct | 1524275753735 |
9 | 357257885227 |
10 | 114403301341 |
11 | 4457775462a |
12 | 1a209526251 |
13 | aa32847764 |
14 | 5773d1b2d7 |
15 | 2e98984711 |
hex | 1aa2f7d7dd |
114403301341 has 4 divisors (see below), whose sum is σ = 130746630112. Its totient is φ = 98059972572.
The previous prime is 114403301333. The next prime is 114403301347. The reversal of 114403301341 is 143103304411.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 114403301341 - 23 = 114403301333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114403301347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8171664375 + ... + 8171664388.
It is an arithmetic number, because the mean of its divisors is an integer number (32686657528).
Almost surely, 2114403301341 is an apocalyptic number.
It is an amenable number.
114403301341 is a deficient number, since it is larger than the sum of its proper divisors (16343328771).
114403301341 is an equidigital number, since it uses as much as digits as its factorization.
114403301341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16343328770.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 114403301341 its reverse (143103304411), we get a palindrome (257506605752).
The spelling of 114403301341 in words is "one hundred fourteen billion, four hundred three million, three hundred one thousand, three hundred forty-one".
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