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114404104051 is a prime number
BaseRepresentation
bin110101010001100000…
…1000001011101110011
3101221022000111122100221
41222203001001131303
53333244422312201
6124320112553511
711160016560646
oct1524301013563
9357260448327
10114404104051
1144578152726
121a209852897
13aa32a68c33
145774089a5d
152e98a924a1
hex1aa3041773

114404104051 has 2 divisors, whose sum is σ = 114404104052. Its totient is φ = 114404104050.

The previous prime is 114404103967. The next prime is 114404104057. The reversal of 114404104051 is 150401404411.

It is a strong prime.

It is an emirp because it is prime and its reverse (150401404411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114404104051 - 217 = 114403972979 is a prime.

It is a super-2 number, since 2×1144041040512 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114404104057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57202052025 + 57202052026.

It is an arithmetic number, because the mean of its divisors is an integer number (57202052026).

Almost surely, 2114404104051 is an apocalyptic number.

114404104051 is a deficient number, since it is larger than the sum of its proper divisors (1).

114404104051 is an equidigital number, since it uses as much as digits as its factorization.

114404104051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1280, while the sum is 25.

Adding to 114404104051 its reverse (150401404411), we get a palindrome (264805508462).

The spelling of 114404104051 in words is "one hundred fourteen billion, four hundred four million, one hundred four thousand, fifty-one".