Base | Representation |
---|---|
bin | 110101010001100000… |
… | …1000001011101110011 |
3 | 101221022000111122100221 |
4 | 1222203001001131303 |
5 | 3333244422312201 |
6 | 124320112553511 |
7 | 11160016560646 |
oct | 1524301013563 |
9 | 357260448327 |
10 | 114404104051 |
11 | 44578152726 |
12 | 1a209852897 |
13 | aa32a68c33 |
14 | 5774089a5d |
15 | 2e98a924a1 |
hex | 1aa3041773 |
114404104051 has 2 divisors, whose sum is σ = 114404104052. Its totient is φ = 114404104050.
The previous prime is 114404103967. The next prime is 114404104057. The reversal of 114404104051 is 150401404411.
It is a strong prime.
It is an emirp because it is prime and its reverse (150401404411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114404104051 - 217 = 114403972979 is a prime.
It is a super-2 number, since 2×1144041040512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114404104057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57202052025 + 57202052026.
It is an arithmetic number, because the mean of its divisors is an integer number (57202052026).
Almost surely, 2114404104051 is an apocalyptic number.
114404104051 is a deficient number, since it is larger than the sum of its proper divisors (1).
114404104051 is an equidigital number, since it uses as much as digits as its factorization.
114404104051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 114404104051 its reverse (150401404411), we get a palindrome (264805508462).
The spelling of 114404104051 in words is "one hundred fourteen billion, four hundred four million, one hundred four thousand, fifty-one".
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