Base | Representation |
---|---|
bin | 110101010001101110… |
… | …1110011110001101001 |
3 | 101221022112201000200012 |
4 | 1222203131303301221 |
5 | 3333303340301103 |
6 | 124320542421305 |
7 | 11160140660153 |
oct | 1524335636151 |
9 | 357275630605 |
10 | 114411650153 |
11 | 44581437179 |
12 | 1a210291835 |
13 | aa344ab898 |
14 | 5775091ad3 |
15 | 2e995832d8 |
hex | 1aa3773c69 |
114411650153 has 2 divisors, whose sum is σ = 114411650154. Its totient is φ = 114411650152.
The previous prime is 114411650131. The next prime is 114411650161. The reversal of 114411650153 is 351056114411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 114154785424 + 256864729 = 337868^2 + 16027^2 .
It is an emirp because it is prime and its reverse (351056114411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114411650153 - 28 = 114411649897 is a prime.
It is not a weakly prime, because it can be changed into another prime (114411652153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57205825076 + 57205825077.
It is an arithmetic number, because the mean of its divisors is an integer number (57205825077).
Almost surely, 2114411650153 is an apocalyptic number.
It is an amenable number.
114411650153 is a deficient number, since it is larger than the sum of its proper divisors (1).
114411650153 is an equidigital number, since it uses as much as digits as its factorization.
114411650153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 114411650153 its reverse (351056114411), we get a palindrome (465467764564).
The spelling of 114411650153 in words is "one hundred fourteen billion, four hundred eleven million, six hundred fifty thousand, one hundred fifty-three".
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