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1144134113134 = 2572067056567
BaseRepresentation
bin10000101001100011101…
…101010001011101101110
311001101012200012000022111
4100221203231101131232
5122221141313110014
62233335152434234
7145442465333215
oct20514355213556
94041180160274
101144134113134
11401251974461
121658a824897a
1383b784a7c0c
143d53ab3a07c
151eb653a02c4
hex10a63b5176e

1144134113134 has 4 divisors (see below), whose sum is σ = 1716201169704. Its totient is φ = 572067056566.

The previous prime is 1144134113131. The next prime is 1144134113149. The reversal of 1144134113134 is 4313114314411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×11441341131342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1144134113096 and 1144134113105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1144134113131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 286033528282 + ... + 286033528285.

It is an arithmetic number, because the mean of its divisors is an integer number (429050292426).

Almost surely, 21144134113134 is an apocalyptic number.

1144134113134 is a deficient number, since it is larger than the sum of its proper divisors (572067056570).

1144134113134 is an equidigital number, since it uses as much as digits as its factorization.

1144134113134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 572067056569.

The product of its digits is 6912, while the sum is 31.

Adding to 1144134113134 its reverse (4313114314411), we get a palindrome (5457248427545).

The spelling of 1144134113134 in words is "one trillion, one hundred forty-four billion, one hundred thirty-four million, one hundred thirteen thousand, one hundred thirty-four".

Divisors: 1 2 572067056567 1144134113134