Base | Representation |
---|---|
bin | 10000101001101101110… |
… | …010101101010100110011 |
3 | 11001101122110120002221221 |
4 | 100221231302231110303 |
5 | 122222013121411011 |
6 | 2233404035125511 |
7 | 145446621436012 |
oct | 20515562552463 |
9 | 4041573502857 |
10 | 1144303310131 |
11 | 401329428693 |
12 | 165934a43897 |
13 | 83ba4568897 |
14 | 3d5553c0a79 |
15 | 1eb75172971 |
hex | 10a6dcad533 |
1144303310131 has 2 divisors, whose sum is σ = 1144303310132. Its totient is φ = 1144303310130.
The previous prime is 1144303310083. The next prime is 1144303310147. The reversal of 1144303310131 is 1310133034411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1144303310131 - 215 = 1144303277363 is a prime.
It is a super-2 number, since 2×11443033101312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1144303310096 and 1144303310105.
It is not a weakly prime, because it can be changed into another prime (1144303310431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572151655065 + 572151655066.
It is an arithmetic number, because the mean of its divisors is an integer number (572151655066).
Almost surely, 21144303310131 is an apocalyptic number.
1144303310131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1144303310131 is an equidigital number, since it uses as much as digits as its factorization.
1144303310131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1144303310131 its reverse (1310133034411), we get a palindrome (2454436344542).
The spelling of 1144303310131 in words is "one trillion, one hundred forty-four billion, three hundred three million, three hundred ten thousand, one hundred thirty-one".
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