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1144322017 is a prime number
BaseRepresentation
bin100010000110100…
…1111011111100001
32221202020120200221
41010031033133201
54320421301032
6305314443041
740233401536
oct10415173741
92852216627
101144322017
11537a38083
1227b293481
131530cb827
14abd98d8d
156a6dd597
hex4434f7e1

1144322017 has 2 divisors, whose sum is σ = 1144322018. Its totient is φ = 1144322016.

The previous prime is 1144321999. The next prime is 1144322029. The reversal of 1144322017 is 7102234411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 890365921 + 253956096 = 29839^2 + 15936^2 .

It is a cyclic number.

It is not a de Polignac number, because 1144322017 - 27 = 1144321889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1144321982 and 1144322000.

It is not a weakly prime, because it can be changed into another prime (1144322077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572161008 + 572161009.

It is an arithmetic number, because the mean of its divisors is an integer number (572161009).

Almost surely, 21144322017 is an apocalyptic number.

It is an amenable number.

1144322017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1144322017 is an equidigital number, since it uses as much as digits as its factorization.

1144322017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 25.

The square root of 1144322017 is about 33827.8290317307. The cubic root of 1144322017 is about 1045.9624282892.

Adding to 1144322017 its reverse (7102234411), we get a palindrome (8246556428).

The spelling of 1144322017 in words is "one billion, one hundred forty-four million, three hundred twenty-two thousand, seventeen".