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11443340031 = 331123046667
BaseRepresentation
bin10101010100001001…
…11000001011111111
31002112111122220102120
422222010320023333
5141413443340111
65131302254023
7553401533244
oct125204701377
932474586376
1011443340031
114942515812
122274427313
131104a31b26
147a7b175cb
1546e964406
hex2aa1382ff

11443340031 has 8 divisors (see below), whose sum is σ = 15749973504. Its totient is φ = 7382799960.

The previous prime is 11443340017. The next prime is 11443340047. The reversal of 11443340031 is 13004334411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11443340031 - 29 = 11443339519 is a prime.

It is a super-2 number, since 2×114433400312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11443339983 and 11443340010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11443340011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61523241 + ... + 61523426.

It is an arithmetic number, because the mean of its divisors is an integer number (1968746688).

Almost surely, 211443340031 is an apocalyptic number.

11443340031 is a deficient number, since it is larger than the sum of its proper divisors (4306633473).

11443340031 is a wasteful number, since it uses less digits than its factorization.

11443340031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 123046701.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 11443340031 its reverse (13004334411), we get a palindrome (24447674442).

The spelling of 11443340031 in words is "eleven billion, four hundred forty-three million, three hundred forty thousand, thirty-one".

Divisors: 1 3 31 93 123046667 369140001 3814446677 11443340031