Base | Representation |
---|---|
bin | 10101010100001001… |
… | …11000001100001111 |
3 | 1002112111122220110011 |
4 | 22222010320030033 |
5 | 141413443340142 |
6 | 5131302254051 |
7 | 553401533266 |
oct | 125204701417 |
9 | 32474586404 |
10 | 11443340047 |
11 | 4942515827 |
12 | 2274427327 |
13 | 1104a31b39 |
14 | 7a7b175dd |
15 | 46e964417 |
hex | 2aa13830f |
11443340047 has 2 divisors, whose sum is σ = 11443340048. Its totient is φ = 11443340046.
The previous prime is 11443340017. The next prime is 11443340053. The reversal of 11443340047 is 74004334411.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11443340047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11443340017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5721670023 + 5721670024.
It is an arithmetic number, because the mean of its divisors is an integer number (5721670024).
Almost surely, 211443340047 is an apocalyptic number.
11443340047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11443340047 is an equidigital number, since it uses as much as digits as its factorization.
11443340047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 11443340047 its reverse (74004334411), we get a palindrome (85447674458).
The spelling of 11443340047 in words is "eleven billion, four hundred forty-three million, three hundred forty thousand, forty-seven".
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