Base | Representation |
---|---|
bin | 11010000001001111111111… |
… | …011111011100101110110000 |
3 | 120000011212222212211202111020 |
4 | 122001033333133130232300 |
5 | 104444401041111222202 |
6 | 1043214431555015440 |
7 | 33050443313414406 |
oct | 3201177737345660 |
9 | 500155885752436 |
10 | 114435100101552 |
11 | 3350a720765a4a |
12 | 10a0235759a580 |
13 | 4bb12505a9989 |
14 | 203898cd69476 |
15 | d36abd81b5bc |
hex | 6813ff7dcbb0 |
114435100101552 has 40 divisors (see below), whose sum is σ = 298671678799536. Its totient is φ = 37751785598976.
The previous prime is 114435100101541. The next prime is 114435100101563. The reversal of 114435100101552 is 255101001534411.
It is an interprime number because it is at equal distance from previous prime (114435100101541) and next prime (114435100101563).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12288988053 + ... + 12288997364.
Almost surely, 2114435100101552 is an apocalyptic number.
114435100101552 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
114435100101552 is an abundant number, since it is smaller than the sum of its proper divisors (184236578697984).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114435100101552 is a wasteful number, since it uses less digits than its factorization.
114435100101552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24577985525 (or 24577985519 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 114435100101552 its reverse (255101001534411), we get a palindrome (369536101635963).
The spelling of 114435100101552 in words is "one hundred fourteen trillion, four hundred thirty-five billion, one hundred million, one hundred one thousand, five hundred fifty-two".
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