Base | Representation |
---|---|
bin | 110101010010101000… |
… | …1101010010111101011 |
3 | 101221101122211222201121 |
4 | 1222211101222113223 |
5 | 3333334124122311 |
6 | 124323545400111 |
7 | 11160660060022 |
oct | 1524521522753 |
9 | 357348758647 |
10 | 114442020331 |
11 | 4459759a7a1 |
12 | 1a21a499037 |
13 | aa3a8831c2 |
14 | 57791198b9 |
15 | 2e9c081b71 |
hex | 1aa546a5eb |
114442020331 has 2 divisors, whose sum is σ = 114442020332. Its totient is φ = 114442020330.
The previous prime is 114442020323. The next prime is 114442020361. The reversal of 114442020331 is 133020244411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114442020331 - 23 = 114442020323 is a prime.
It is a super-2 number, since 2×1144420203312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114442020296 and 114442020305.
It is not a weakly prime, because it can be changed into another prime (114442020361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57221010165 + 57221010166.
It is an arithmetic number, because the mean of its divisors is an integer number (57221010166).
Almost surely, 2114442020331 is an apocalyptic number.
114442020331 is a deficient number, since it is larger than the sum of its proper divisors (1).
114442020331 is an equidigital number, since it uses as much as digits as its factorization.
114442020331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 114442020331 its reverse (133020244411), we get a palindrome (247462264742).
The spelling of 114442020331 in words is "one hundred fourteen billion, four hundred forty-two million, twenty thousand, three hundred thirty-one".
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