114443131044333 has 64 divisors (see below), whose sum is σ = 188316276592640. Its totient is φ = 60201011662848.

The previous prime is 114443131044283. The next prime is 114443131044353. The reversal of 114443131044333 is 333440131344411.

It is a happy number.

It is not a de Polignac number, because 114443131044333 - 2⁹ = 114443131043821 is a prime.

It is a super-2 number, since 2×114443131044333² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 114443131044291 and 114443131044300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114443131044353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1351547085 + ... + 1351631757.

It is an arithmetic number, because the mean of its divisors is an integer number (2942441821760).

Almost surely, 2^{114443131044333} is an apocalyptic number.

114443131044333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

114443131044333 is a deficient number, since it is larger than the sum of its proper divisors (73873145548307).

114443131044333 is a wasteful number, since it uses less digits than its factorization.

114443131044333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 98138.

The product of its (nonzero) digits is 248832, while the sum is 39.

Adding to 114443131044333 its reverse (333440131344411), we get a palindrome (447883262388744).

The spelling of 114443131044333 in words is "one hundred fourteen trillion, four hundred forty-three billion, one hundred thirty-one million, forty-four thousand, three hundred thirty-three".