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11445122454113 is a prime number
BaseRepresentation
bin1010011010001100011001…
…1101010101001001100001
31111112010212021002012211102
42212203012131111021201
53000004102322012423
640201452222324145
72260611542464565
oct246430635251141
944463767065742
1011445122454113
1137129382849a7
12134a184429655
1365036914948a
142b7d383616a5
1514caa962dc28
hexa68c6755261

11445122454113 has 2 divisors, whose sum is σ = 11445122454114. Its totient is φ = 11445122454112.

The previous prime is 11445122454053. The next prime is 11445122454131. The reversal of 11445122454113 is 31145422154411.

Together with next prime (11445122454131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11132252269009 + 312870185104 = 3336503^2 + 559348^2 .

It is a cyclic number.

It is not a de Polignac number, because 11445122454113 - 216 = 11445122388577 is a prime.

It is not a weakly prime, because it can be changed into another prime (11445122454313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5722561227056 + 5722561227057.

It is an arithmetic number, because the mean of its divisors is an integer number (5722561227057).

Almost surely, 211445122454113 is an apocalyptic number.

It is an amenable number.

11445122454113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11445122454113 is an equidigital number, since it uses as much as digits as its factorization.

11445122454113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 76800, while the sum is 38.

The spelling of 11445122454113 in words is "eleven trillion, four hundred forty-five billion, one hundred twenty-two million, four hundred fifty-four thousand, one hundred thirteen".