Base | Representation |
---|---|
bin | 1010011010001110010111… |
… | …1010010110000000011111 |
3 | 1111112012020001001010022021 |
4 | 2212203211322112000133 |
5 | 3000011142414403003 |
6 | 40202020433001011 |
7 | 2260630611036016 |
oct | 246434572260037 |
9 | 44465201033267 |
10 | 11445650153503 |
11 | 37130891402a5 |
12 | 134a2b10b3167 |
13 | 65042157c337 |
14 | 2b7d88487a7d |
15 | 14cadab192bd |
hex | a68e5e9601f |
11445650153503 has 2 divisors, whose sum is σ = 11445650153504. Its totient is φ = 11445650153502.
The previous prime is 11445650153411. The next prime is 11445650153519. The reversal of 11445650153503 is 30535105654411.
11445650153503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11445650153503 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11445650153503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11445650153533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5722825076751 + 5722825076752.
It is an arithmetic number, because the mean of its divisors is an integer number (5722825076752).
Almost surely, 211445650153503 is an apocalyptic number.
11445650153503 is a deficient number, since it is larger than the sum of its proper divisors (1).
11445650153503 is an equidigital number, since it uses as much as digits as its factorization.
11445650153503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540000, while the sum is 43.
The spelling of 11445650153503 in words is "eleven trillion, four hundred forty-five billion, six hundred fifty million, one hundred fifty-three thousand, five hundred three".
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