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11446005510403 is a prime number
BaseRepresentation
bin1010011010001111101100…
…0101111011000100000011
31111112020010210201010022221
42212203323011323010003
53000012404402313103
640202120005311511
72260642454363662
oct246437305730403
944466123633287
1011446005510403
113713250794192
12134a390105597
1365047a08c8a9
142b7dbd74add9
1514cb0be101bd
hexa68fb17b103

11446005510403 has 2 divisors, whose sum is σ = 11446005510404. Its totient is φ = 11446005510402.

The previous prime is 11446005510353. The next prime is 11446005510451. The reversal of 11446005510403 is 30401550064411.

11446005510403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11446005510403 is a prime.

It is a super-2 number, since 2×114460055104032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11446005510493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5723002755201 + 5723002755202.

It is an arithmetic number, because the mean of its divisors is an integer number (5723002755202).

Almost surely, 211446005510403 is an apocalyptic number.

11446005510403 is a deficient number, since it is larger than the sum of its proper divisors (1).

11446005510403 is an equidigital number, since it uses as much as digits as its factorization.

11446005510403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 11446005510403 its reverse (30401550064411), we get a palindrome (41847555574814).

The spelling of 11446005510403 in words is "eleven trillion, four hundred forty-six billion, five million, five hundred ten thousand, four hundred three".