Base | Representation |
---|---|
bin | 1010011010010111011011… |
… | …1100110100000000101011 |
3 | 1111112102111121210210001121 |
4 | 2212211312330310000223 |
5 | 3000031133333401003 |
6 | 40203102120000111 |
7 | 2261045116104646 |
oct | 246456674640053 |
9 | 44472447723047 |
10 | 11448083497003 |
11 | 371411775728a |
12 | 134a870000037 |
13 | 65071b740a6a |
14 | 2b8139706a5d |
15 | 14cbce579cbd |
hex | a6976f3402b |
11448083497003 has 2 divisors, whose sum is σ = 11448083497004. Its totient is φ = 11448083497002.
The previous prime is 11448083496937. The next prime is 11448083497021. The reversal of 11448083497003 is 30079438084411.
It is a happy number.
11448083497003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11448083497003 - 229 = 11447546626091 is a prime.
It is not a weakly prime, because it can be changed into another prime (11448083497073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5724041748501 + 5724041748502.
It is an arithmetic number, because the mean of its divisors is an integer number (5724041748502).
Almost surely, 211448083497003 is an apocalyptic number.
11448083497003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11448083497003 is an equidigital number, since it uses as much as digits as its factorization.
11448083497003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2322432, while the sum is 52.
The spelling of 11448083497003 in words is "eleven trillion, four hundred forty-eight billion, eighty-three million, four hundred ninety-seven thousand, three".
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