Base | Representation |
---|---|
bin | 10000101010010010000… |
… | …110001101001101110110 |
3 | 11001110012220200010221000 |
4 | 100222102012031031312 |
5 | 122224240033320040 |
6 | 2233544314104130 |
7 | 145500665560641 |
oct | 20522206151566 |
9 | 4043186603830 |
10 | 1144912401270 |
11 | 4016112258a0 |
12 | 165a84a1b046 |
13 | 83c707c8441 |
14 | 3d5b2252a58 |
15 | 1ebad889130 |
hex | 10a9218d376 |
1144912401270 has 256 divisors, whose sum is σ = 3528700277760. Its totient is φ = 261070387200.
The previous prime is 1144912401221. The next prime is 1144912401277. The reversal of 1144912401270 is 721042194411.
It is a happy number.
1144912401270 is a `hidden beast` number, since 1 + 1 + 4 + 491 + 2 + 40 + 127 + 0 = 666.
It is a super-2 number, since 2×11449124012702 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1144912401277) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 97591305 + ... + 97603035.
It is an arithmetic number, because the mean of its divisors is an integer number (13783985460).
Almost surely, 21144912401270 is an apocalyptic number.
1144912401270 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 1144912401270, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1764350138880).
1144912401270 is an abundant number, since it is smaller than the sum of its proper divisors (2383787876490).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1144912401270 is a wasteful number, since it uses less digits than its factorization.
1144912401270 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13708 (or 13702 counting only the distinct ones).
The product of its (nonzero) digits is 16128, while the sum is 36.
Adding to 1144912401270 its reverse (721042194411), we get a palindrome (1865954595681).
The spelling of 1144912401270 in words is "one trillion, one hundred forty-four billion, nine hundred twelve million, four hundred one thousand, two hundred seventy".
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