Base | Representation |
---|---|
bin | 110101010100011000… |
… | …0001001011001101001 |
3 | 101221112201121002221022 |
4 | 1222220300021121221 |
5 | 3333444041442101 |
6 | 124333431422225 |
7 | 11162265601103 |
oct | 1525060113151 |
9 | 357481532838 |
10 | 114500343401 |
11 | 44617505784 |
12 | 1a235b24975 |
13 | aa49993ab2 |
14 | 5782b7c573 |
15 | 2ea2252a1b |
hex | 1aa8c09669 |
114500343401 has 2 divisors, whose sum is σ = 114500343402. Its totient is φ = 114500343400.
The previous prime is 114500343379. The next prime is 114500343407. The reversal of 114500343401 is 104343005411.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113869128025 + 631215376 = 337445^2 + 25124^2 .
It is a cyclic number.
It is not a de Polignac number, because 114500343401 - 230 = 113426601577 is a prime.
It is a super-2 number, since 2×1145003434012 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114500343407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57250171700 + 57250171701.
It is an arithmetic number, because the mean of its divisors is an integer number (57250171701).
Almost surely, 2114500343401 is an apocalyptic number.
It is an amenable number.
114500343401 is a deficient number, since it is larger than the sum of its proper divisors (1).
114500343401 is an equidigital number, since it uses as much as digits as its factorization.
114500343401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 114500343401 its reverse (104343005411), we get a palindrome (218843348812).
The spelling of 114500343401 in words is "one hundred fourteen billion, five hundred million, three hundred forty-three thousand, four hundred one".
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