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1145004354353 is a prime number
BaseRepresentation
bin10000101010010111100…
…100111110101100110001
311001110110022200211211202
4100222113210332230301
5122224432103314403
62234001401020545
7145503163266506
oct20522744765461
94043408624752
101145004354353
11401659120582
12165aab784755
1383c86882352
143d5c054b4ad
151ebb699e688
hex10a9793eb31

1145004354353 has 2 divisors, whose sum is σ = 1145004354354. Its totient is φ = 1145004354352.

The previous prime is 1145004354337. The next prime is 1145004354401. The reversal of 1145004354353 is 3534534005411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1072929287329 + 72075067024 = 1035823^2 + 268468^2 .

It is a cyclic number.

It is not a de Polignac number, because 1145004354353 - 24 = 1145004354337 is a prime.

It is a super-2 number, since 2×11450043543532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1145004350353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572502177176 + 572502177177.

It is an arithmetic number, because the mean of its divisors is an integer number (572502177177).

Almost surely, 21145004354353 is an apocalyptic number.

It is an amenable number.

1145004354353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1145004354353 is an equidigital number, since it uses as much as digits as its factorization.

1145004354353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 1145004354353 its reverse (3534534005411), we get a palindrome (4679538359764).

The spelling of 1145004354353 in words is "one trillion, one hundred forty-five billion, four million, three hundred fifty-four thousand, three hundred fifty-three".