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1145044533407 is a prime number
BaseRepresentation
bin10000101010011001111…
…110010000000010011111
311001110120010022011010212
4100222121332100002133
5122230022400032112
62234005354123035
7145504161641555
oct20523176200237
94043503264125
101145044533407
11401679873705
12165b0112047b
1383c91cac538
143d5c5a09bd5
151ebba289522
hex10a99f9009f

1145044533407 has 2 divisors, whose sum is σ = 1145044533408. Its totient is φ = 1145044533406.

The previous prime is 1145044533359. The next prime is 1145044533419. The reversal of 1145044533407 is 7043354405411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1145044533407 - 26 = 1145044533343 is a prime.

It is a super-2 number, since 2×11450445334072 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1145044533427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572522266703 + 572522266704.

It is an arithmetic number, because the mean of its divisors is an integer number (572522266704).

Almost surely, 21145044533407 is an apocalyptic number.

1145044533407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1145044533407 is an equidigital number, since it uses as much as digits as its factorization.

1145044533407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 403200, while the sum is 41.

Adding to 1145044533407 its reverse (7043354405411), we get a palindrome (8188398938818).

The spelling of 1145044533407 in words is "one trillion, one hundred forty-five billion, forty-four million, five hundred thirty-three thousand, four hundred seven".