Base | Representation |
---|---|
bin | 11010000010010101111100… |
… | …000011010001111001111110 |
3 | 120000110001212000200000110012 |
4 | 122002111330003101321332 |
5 | 110002113344301010324 |
6 | 1043313132302543222 |
7 | 33056042416604543 |
oct | 3202257403217176 |
9 | 500401760600405 |
10 | 114510204313214 |
11 | 33539561072866 |
12 | 10a14a17897b12 |
13 | 4bb835c33c6c8 |
14 | 203c47580cbca |
15 | d38a170bb20e |
hex | 68257c0d1e7e |
114510204313214 has 4 divisors (see below), whose sum is σ = 171765306469824. Its totient is φ = 57255102156606.
The previous prime is 114510204313147. The next prime is 114510204313223. The reversal of 114510204313214 is 412313402015411.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×1145102043132143 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28627551078302 + ... + 28627551078305.
It is an arithmetic number, because the mean of its divisors is an integer number (42941326617456).
Almost surely, 2114510204313214 is an apocalyptic number.
114510204313214 is a deficient number, since it is larger than the sum of its proper divisors (57255102156610).
114510204313214 is an equidigital number, since it uses as much as digits as its factorization.
114510204313214 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57255102156609.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 114510204313214 its reverse (412313402015411), we get a palindrome (526823606328625).
The spelling of 114510204313214 in words is "one hundred fourteen trillion, five hundred ten billion, two hundred four million, three hundred thirteen thousand, two hundred fourteen".
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