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114510204313214 = 257255102156607
BaseRepresentation
bin11010000010010101111100…
…000011010001111001111110
3120000110001212000200000110012
4122002111330003101321332
5110002113344301010324
61043313132302543222
733056042416604543
oct3202257403217176
9500401760600405
10114510204313214
1133539561072866
1210a14a17897b12
134bb835c33c6c8
14203c47580cbca
15d38a170bb20e
hex68257c0d1e7e

114510204313214 has 4 divisors (see below), whose sum is σ = 171765306469824. Its totient is φ = 57255102156606.

The previous prime is 114510204313147. The next prime is 114510204313223. The reversal of 114510204313214 is 412313402015411.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×1145102043132143 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28627551078302 + ... + 28627551078305.

It is an arithmetic number, because the mean of its divisors is an integer number (42941326617456).

Almost surely, 2114510204313214 is an apocalyptic number.

114510204313214 is a deficient number, since it is larger than the sum of its proper divisors (57255102156610).

114510204313214 is an equidigital number, since it uses as much as digits as its factorization.

114510204313214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57255102156609.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 114510204313214 its reverse (412313402015411), we get a palindrome (526823606328625).

The spelling of 114510204313214 in words is "one hundred fourteen trillion, five hundred ten billion, two hundred four million, three hundred thirteen thousand, two hundred fourteen".

Divisors: 1 2 57255102156607 114510204313214