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114510323251451 is a prime number
BaseRepresentation
bin11010000010010110000011…
…001000111111100011111011
3120000110002011022110201001002
4122002112003020333203323
5110002114120223021301
61043313152152115215
733056045362554341
oct3202260310774373
9500402138421032
10114510323251451
1133539612219926
1210a14a4b695b0b
134bb837ab8426a
14203c48752d991
15d38a2276216b
hex68258323f8fb

114510323251451 has 2 divisors, whose sum is σ = 114510323251452. Its totient is φ = 114510323251450.

The previous prime is 114510323251321. The next prime is 114510323251469. The reversal of 114510323251451 is 154152323015411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114510323251451 - 238 = 114235445344507 is a prime.

It is a super-2 number, since 2×1145103232514512 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114540323251451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57255161625725 + 57255161625726.

It is an arithmetic number, because the mean of its divisors is an integer number (57255161625726).

Almost surely, 2114510323251451 is an apocalyptic number.

114510323251451 is a deficient number, since it is larger than the sum of its proper divisors (1).

114510323251451 is an equidigital number, since it uses as much as digits as its factorization.

114510323251451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 38.

Adding to 114510323251451 its reverse (154152323015411), we get a palindrome (268662646266862).

The spelling of 114510323251451 in words is "one hundred fourteen trillion, five hundred ten billion, three hundred twenty-three million, two hundred fifty-one thousand, four hundred fifty-one".