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114511244341127 is a prime number
BaseRepresentation
bin11010000010010110111010…
…000010101010111110000111
3120000110011112111122220112112
4122002112322002222332013
5110002123012022404002
61043313423414211235
733056110245651104
oct3202267202527607
9500404474586475
10114511244341127
1133539a45146167
1210a15068053b1b
134bb849695303a
14203c5339b9aab
15d38a78557852
hex6825ba0aaf87

114511244341127 has 2 divisors, whose sum is σ = 114511244341128. Its totient is φ = 114511244341126.

The previous prime is 114511244341079. The next prime is 114511244341171. The reversal of 114511244341127 is 721143442115411.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114511244341127 is a prime.

It is a super-2 number, since 2×1145112443411272 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114511244341327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57255622170563 + 57255622170564.

It is an arithmetic number, because the mean of its divisors is an integer number (57255622170564).

Almost surely, 2114511244341127 is an apocalyptic number.

114511244341127 is a deficient number, since it is larger than the sum of its proper divisors (1).

114511244341127 is an equidigital number, since it uses as much as digits as its factorization.

114511244341127 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 107520, while the sum is 41.

Adding to 114511244341127 its reverse (721143442115411), we get a palindrome (835654686456538).

The spelling of 114511244341127 in words is "one hundred fourteen trillion, five hundred eleven billion, two hundred forty-four million, three hundred forty-one thousand, one hundred twenty-seven".