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1145113447 is a prime number
BaseRepresentation
bin100010001000001…
…0000101101100111
32221210201210100011
41010100100231213
54321122112242
6305343431051
740243206112
oct10420205547
92853653304
101145113447
11538428755
1227b5b5487
13153317b2a
14ac123579
156a7e7d17
hex44410b67

1145113447 has 2 divisors, whose sum is σ = 1145113448. Its totient is φ = 1145113446.

The previous prime is 1145113439. The next prime is 1145113471. The reversal of 1145113447 is 7443115411.

It is a weak prime.

It is an emirp because it is prime and its reverse (7443115411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1145113447 - 23 = 1145113439 is a prime.

It is a super-2 number, since 2×11451134472 = 2622569613000443618, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1145113747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572556723 + 572556724.

It is an arithmetic number, because the mean of its divisors is an integer number (572556724).

Almost surely, 21145113447 is an apocalyptic number.

1145113447 is a deficient number, since it is larger than the sum of its proper divisors (1).

1145113447 is an equidigital number, since it uses as much as digits as its factorization.

1145113447 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6720, while the sum is 31.

The square root of 1145113447 is about 33839.5249227881. The cubic root of 1145113447 is about 1046.2035070720.

Adding to 1145113447 its reverse (7443115411), we get a palindrome (8588228858).

The spelling of 1145113447 in words is "one billion, one hundred forty-five million, one hundred thirteen thousand, four hundred forty-seven".