1145140001311 has 2 divisors, whose sum is σ = 1145140001312. Its totient is φ = 1145140001310.

The previous prime is 1145140001251. The next prime is 1145140001329. The reversal of 1145140001311 is 1131000415411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1145140001311 - 2¹⁵ = 1145139968543 is a prime.

It is a super-2 number, since 2×1145140001311² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1145140001371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 572570000655 + 572570000656.

It is an arithmetic number, because the mean of its divisors is an integer number (572570000656).

Almost surely, 2^{1145140001311} is an apocalyptic number.

1145140001311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1145140001311 is an equidigital number, since it uses as much as digits as its factorization.

1145140001311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 1145140001311 its reverse (1131000415411), we get a palindrome (2276140416722).

The spelling of 1145140001311 in words is "one trillion, one hundred forty-five billion, one hundred forty million, one thousand, three hundred eleven".