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11452015202104 = 231975342205277
BaseRepresentation
bin1010011010100110000101…
…0011000100111100111000
31111112210122122000002112001
42212221201103010330320
53000112211342431404
640204552210030344
72261244420046021
oct246514123047470
944483578002461
1011452015202104
113715855034544
12134b5888783b4
13650bc716ca99
142b83cd95dc48
1514cd5e80e7a4
hexa6a614c4f38

11452015202104 has 16 divisors (see below), whose sum is σ = 22602661583400. Its totient is φ = 5424638779872.

The previous prime is 11452015202101. The next prime is 11452015202107. The reversal of 11452015202104 is 40120251025411.

It is an interprime number because it is at equal distance from previous prime (11452015202101) and next prime (11452015202107).

It is a super-2 number, since 2×114520152021042 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11452015202101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37671102487 + ... + 37671102790.

Almost surely, 211452015202104 is an apocalyptic number.

It is an amenable number.

11452015202104 is a deficient number, since it is larger than the sum of its proper divisors (11150646381296).

11452015202104 is a wasteful number, since it uses less digits than its factorization.

11452015202104 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75342205302 (or 75342205298 counting only the distinct ones).

The product of its (nonzero) digits is 3200, while the sum is 28.

Adding to 11452015202104 its reverse (40120251025411), we get a palindrome (51572266227515).

The spelling of 11452015202104 in words is "eleven trillion, four hundred fifty-two billion, fifteen million, two hundred two thousand, one hundred four".

Divisors: 1 2 4 8 19 38 76 152 75342205277 150684410554 301368821108 602737642216 1431501900263 2863003800526 5726007601052 11452015202104