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114523141201471 is a prime number
BaseRepresentation
bin11010000010100001111111…
…001001100101111000111111
3120000111022020121201000212201
4122002201333021211320333
5110002321343121421341
61043323112121212331
733060011125415122
oct3202417711457077
9500438217630781
10114523141201471
1133543a9a661452
1210a174283310a7
134bb9641614c82
14203cd41a2a3b9
15d39022c03331
hex68287f265e3f

114523141201471 has 2 divisors, whose sum is σ = 114523141201472. Its totient is φ = 114523141201470.

The previous prime is 114523141201429. The next prime is 114523141201487. The reversal of 114523141201471 is 174102141325411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114523141201471 - 227 = 114523006983743 is a prime.

It is a super-3 number, since 3×1145231412014713 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 114523141201471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114523141201571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57261570600735 + 57261570600736.

It is an arithmetic number, because the mean of its divisors is an integer number (57261570600736).

Almost surely, 2114523141201471 is an apocalyptic number.

114523141201471 is a deficient number, since it is larger than the sum of its proper divisors (1).

114523141201471 is an equidigital number, since it uses as much as digits as its factorization.

114523141201471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26880, while the sum is 37.

Adding to 114523141201471 its reverse (174102141325411), we get a palindrome (288625282526882).

The spelling of 114523141201471 in words is "one hundred fourteen trillion, five hundred twenty-three billion, one hundred forty-one million, two hundred one thousand, four hundred seventy-one".